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3x^2=1.6*10^-30
We move all terms to the left:
3x^2-(1.6*10^-30)=0
We add all the numbers together, and all the variables
3x^2-30-1.6E=0
We add all the numbers together, and all the variables
3x^2-34.349250925534=0
a = 3; b = 0; c = -34.349250925534;
Δ = b2-4ac
Δ = 02-4·3·(-34.349250925534)
Δ = 412.19101110641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{412.19101110641}}{2*3}=\frac{0-\sqrt{412.19101110641}}{6} =-\frac{\sqrt{}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{412.19101110641}}{2*3}=\frac{0+\sqrt{412.19101110641}}{6} =\frac{\sqrt{}}{6} $
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